Advanced Level Organic Chemistry: Mass spectrum of 2-methylbut-2-ene (2-methyl-2-butene)

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Interpreting the mass spectrum of 2-methylbut-2-ene (2-methyl-2-butene)

[Author ©  Dr Phil Brown PhD: Doc Brown's advanced level organic chemistry exam revision notes suitable for students of UK A level chemistry courses & US K12 grade 11, grade 12 and AP honors chemistry courses: Molecular spectrometry - analysing the mass spectrum of 2-methylbut-2-ene  [spectra page updated Mar 13th 2026 *]

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Introductory note on the mass spectrum of 2-methylbut-2-ene

Students and teachers please note my explanation of the mass spectrum of 2-methylbut-2-ene is designed for advanced, but pre-university, chemistry courses.

If M represents the 2-methylbut-2-ene molecule, the initial ionisation to give the molecular ion is:

M(g) + high KE e-  ==> [M]+(g) + 2e- and for fragmentation equations assume [M]+ is the start of the processes and all species are in a gaseous state.

I've not usually shown an unpaired electron on e.g. an ion or a non-ionised alkyl radical R e.g.

[M]+ ==> [X]+  +  R, but you should be aware this is a more accurate depiction of some processes.

I've used simplified equations to show how some of the ions that might be formed in the fragmentation pattern for the mass spectrum of 2-methylbut-2-ene and only the formation of singly charged positive are considered for the mass spectrum of 2-methylbut-2-ene.

I've included a stick diagram and table of m/z ions for the mass spectrum of 2-methylbut-2-ene and doing the mass spectrum analysis under standard conditions, databases can be compiled based on complex fingerprint patterns, often involving the relative intensities of many fragment ions, and used to identify compounds including 2-methylbut-2-ene.

In selected cases, where two different fragment ions have the same integer m/z value, I've pointed out that modern mass spectrometers can measure relative ion mass to four decimal places. So, using accurate isotopic masses, I've calculated the accurate ion masses, BUT strictly speaking, 0.0005 should be deducted for singly charged ions to account for the loss of the electron in their formation. I have NOT done this, but the mass spectrometer software does!

C5H10 mass spectrum of 2-methylbut-2-ene (2-methyl-2-butene) fragmentation pattern of m/z m/e ions for analysis and identification of 2-methylbut-2-ene (2-methyl-2-butene) image diagram doc brown's advanced organic chemistry revision notes 

2-methylbut-2-ene C5H10 (CH3)2C=CHCH3 alkenes structure and naming (c) doc b , alkenes structure and naming (c) doc b

The molecular structure and naming of alkenes

Interpreting the fragmentation pattern of the mass spectrum of 2-methylbut-2-ene (2-methyl-2-butene)

[M]+ is the molecular ion peak (M) with an m/z of 70 corresponding to [C5H10]+, the original 2-methylbut-2-ene (2-methyl-2-butene) molecule minus an electron, [(CH3)2C=CHCH3]+

The small M+1 peak at m/z 71, corresponds to an ionised 2-methylbut-2-ene (2-methyl-2-butene) molecule with one 13C atom in it

i.e. an ionised 2-methylbut-2-ene (2-methyl-2-butene) molecule of formula [13C12C4H10]+

Identifying the species giving the most prominent peaks (apart from M) in the fragmentation pattern of 2-methylbut-2-ene (2-methyl-2-butene).

The most abundant ion of the molecule under mass spectrometry investigation (2-methylbut-2-ene) is usually given an arbitrary abundance value of 100, called the base ion peak, and all other abundances ('intensities') are measured against it.

The base peak ion for the mass spectrum of 2-methylbut-2-ene is the m/z 55 ion [C4H7]+

The parent molecular ion is the m/z of 70 ion [C5H10]+  or  [(CH3)2C=CHCH3]+

m/z value of [fragment]+ 69 56 55 53 43 42 41 39 29 27
[molecular fragment]+ [C5H9]+ [C4H8]+ [C4H7]+ [C4H5]+ [C3H7]+ [C3H6]+ [C3H5]+ [C3H3]+ [C2H5]+ [C2H3]+

Analysing and explaining the principal ions in the fragmentation pattern of the mass spectrum of 2-methylbut-2-ene (2-methyl-2-butene)

PLEASE NOTE I have found it difficult to find 'authentic' equations to explain mass spectra fragmentation patterns and it is complex chemistry! I've identified the formulae of the ionised fragments on the mass spectrum diagram, but the equations are from the internet or my conjecture as to how the ions might be formed - please take care in using the information, especially for assignments at university or pre-university level.

Suggested equations to explain some of the most abundant ion peaks of 2-methylbut-2-ene (2-methyl-2-butene)

Formation of m/z 69 ion

[(CH3)2C=CHCH3]+  ===>  [C5H9]+  +  H

Loss of a proton from various sites on the molecule

mass change 70 - 1 = 69 (M-1 ion)

Formation of m/z 55 and 56 ions

[(CH3)2C=CHCH3]+  ===>  [C4H7]+  +  CH3

C-C bond scission to lose a methyl group from the molecular ion.

Mass change 70 - 15 = 55 (M-15 ion)

The m/z 55 ion is the base peak ion, the most abundant and 'stable' ion fragment and formed by the loss of a methyl group from the parent molecular ion.

The m/z 55 ion can lose hydrogen atoms to give the m/z 53 ion.

The m/z 56 ion could be [C4H8]+

OR formed as but containing a 13C isotope i.e. [13C12C3H7]+

An accurate mass spectrometer sorts this out, measuring relative fragment ion masses to four decimal places e.g. using very accurate relative isotopic masses,

1H = 1.0078,  12C = 12.0000,  13C = 13.0034, you can then calculate (predict) that the accurate relative ion masses are:

For m/z 56: [13C12C3H7]+ = 56.0580, [C4H8]+ = 56.0624, a difference of 0.0044 in relative ion mass.

Formation of m/z 42 ion

[(CH3)2C=CHCH3]+  ===>  [C3H6]+  +  C2H4

mass change 70 - 28 = 42 (M-28 ion)

Formed by C-C bond scission. proton migration, and loss of non-ionised ethene molecule.

The m/z 42 and 43 ions can lose hydrogen atoms to give the m/z 41 and 39 ions.

Formation of m/z 29 and 27 ions

[C2H5]+ and  [C2H5]+ will be formed by the fragmentation and/or loss of hydrogen atoms for larger ions e.g. [C3-4H5-10]+


alkenes structure and naming (c) doc bSummary of key points for the mass spectrum of 2-methylbut-2-ene plus extra exam revision comments and practice questions

A structured breakdown of the mass spectrum of 2-methylbut-2-ene (C5H10), tailored for advanced A-level chemistry revision.

This includes key peaks, fragmentation origins, common misconceptions, and exam strategies across major exam boards.


Key Concepts in Mass Spectrometry of 2-Methylbut-2-ene

  • Molecular ion (M⁺): Formed by electron impact ionization, giving the full molecular mass.
  • Fragmentation: Occurs via cleavage of bonds, often forming carbocations.
  • Base peak: The most intense peak, often from the most stable fragment.
  • Isotopic peaks: Minor peaks due to natural abundance of isotopes (e.g. ¹³C).

Prominent m/z Peaks and Fragment Origins in the mass spectrum of 2-methylbut-2-ene

m/z Ion Fragment Origin of Fragmentation Notes
70 C5H10₀⁺ (M⁺) Molecular ion Confirms molecular mass of 70
55 C4H7 Loss of CH3• (methyl radical) Allylic carbocation, relatively stable, base ion peak
41 C3H5 Further cleavage of alkyl chain Common fragment in alkenes, m/z ions 39 and 42 quite prominent
29 C2H5 Ethyl fragment Often seen in hydrocarbon mass spectra
15 CH3 Methyl cation Small, stable fragment

The base peak is typically m/z = 55, due to the stability of the allylic carbocation formed after methyl loss.


Common Misconceptions about the mass spectrum of 2-methylbut-2-ene (see also below)

Misconception Clarification
The molecular ion is always the base peak Not true — base peak reflects most stable fragment, not necessarily M⁺
All fragments are radicals Only ions are detected; neutral radicals are not seen in the spectrum
Fragmentation is random It follows predictable patterns based on bond strength and carbocation stability
Isotopic peaks are impurities They reflect natural isotope abundance (e.g. ¹³C at m/z = 71)

Exam Revision Tips for questions involving the mass spectrum of 2-methylbut-2-ene

(AQA, Edexcel, OCR, WJEC, CCEA, CIE, IB) (see also above)

What to Focus On:

  • Identify M⁺ peak: Confirms molecular mass (m/z = 70 for C5H10).
  • Recognise base peak: Often the most stable carbocation (m/z = 55 in this case).
  • Use fragmentation logic: Predict fragments based on bond cleavage and stability.
  • Isotope peaks: Small peaks at M+1 due to ¹³C — useful for estimating carbon count.

Exam-Style Strategy:

  • Step 1: Locate M⁺ peak and base peak.
  • Step 2: Deduce possible fragments and their origin.
  • Step 3: Use fragmentation patterns to confirm structure.
  • Step 4: Avoid overinterpreting minor peaks unless asked about isotopes.

alkenes structure and naming (c) doc bPractice questions based on the mass spectrum of 2-methylbut-2-ene

Question 1 — Base peak origin and stabilisation based on the EI mass spectrum of 2-methyl-2-butene

Which explanation best accounts for the base peak at m/z 55 in the EI mass spectrum of 2‑methylbut‑2‑ene (C5H10)?

  1. Formation of an acylium ion after oxygen insertion leading to m/z 55
  2. Direct formation of a saturated tert‑butyl cation C4H9+ (m/z 57) by simple homolytic cleavage
  3. Loss of a methyl radical from M•+ producing a resonance‑stabilised C4H7+ (m/z 55)
  4. Loss of ethene (C2H4, 28) from M•+ giving C3H6+ (m/z 42) which rearranges to m/z 55

Correct answer: C

Model answer

  • EI produces the molecular radical cation M•+ (m/z 70). A favourable fragmentation is loss of •CH3 (15 u) from positions adjacent to the internal double bond, yielding C4H7+ (m/z 55). That C4 fragment is stabilised by alkenyl/allylic delocalisation and by branching at C‑2, so this fragment is particularly abundant and appears as the base peak.

Distractor analysis

  • A is incorrect because acylium ions require oxygen/carbonyl chemistry, not present here.
  • B is incorrect because C4H9+ (m/z 57) is a saturated carbocation and is not the dominant EI fragment for this alkene.
  • D is incorrect because loss of C2H4 yields m/z 42; rearrangement to 55 is not the principal EI route.

Question 2 — Isomer discrimination by relative fragment intensities based on the EI mass spectrum of 2-methyl-2-butene

Which spectral feature most reliably distinguishes 2‑methylbut‑2‑ene from its positional isomer 2‑methylbut‑1‑ene under EI conditions?

  1. Different molecular ion masses because branching changes M+
  2. A dominant base peak at m/z 55 for 2‑methylbut‑2‑ene due to formation of stabilised C4H7+
  3. Presence of a chlorine isotope pattern in 2‑methylbut‑2‑ene but not in 2‑methylbut‑1‑ene
  4. A dominant peak at m/z 41 for 2‑methylbut‑2‑ene from allylic cleavage

Correct answer: B

Model answer

  • Both isomers have M+ = 70. The diagnostic difference is fragmentation: the internal, branched alkene (2‑methylbut‑2‑ene) favours loss of •CH3 to give a stabilised C4H7+ (m/z 55). The terminal isomer (2‑methylbut‑1‑ene) more commonly produces allylic C3 fragments (C3H5+, m/z 41). Thus a relatively intense m/z 55 indicates the 2‑ene.

Distractor analysis

  • A is false because branching does not change nominal molecular mass; both are C5H10 → m/z 70.
  • C is irrelevant; no halogen present.
  • D is reversed: m/z 41 (allylic fragment) is more characteristic and stronger for terminal 1‑enes, not for the branched internal 2‑ene.

Question 3 — Competing fragmentation channels and mechanistic detail based on the EI mass spectrum of 2-methyl-2-butene

The EI spectrum shows a strong peak at m/z 55 and a moderate peak at m/z 41.

Which mechanistic statement best explains their relative intensities?

  1. m/z 41 is the molecular ion and therefore should be the base peak; m/z 55 is an oxidation artefact
  2. m/z 55 arises from halogen loss; m/z 41 from halogenated side products
  3. m/z 55 (C4H7+) is favoured because loss of •CH3 adjacent to the internal double bond yields a delocalised alkenyl/allylic cation; m/z 41 (C3H5+) arises from alternative allylic cleavage and is less stabilised here
  4. m/z 55 and m/z 41 are produced by identical symmetric cleavages and therefore must be equal in intensity

Correct answer: C

Model answer

  • Two principal EI fragmentation channels compete: (1) loss of •CH3 → C4H7+ (m/z 55), stabilised by delocalisation across the alkene and branching, producing the base peak; (2) C–C cleavage to give C3H5+ (m/z 41) (allylic fragment) which is possible but yields a less stabilised fragment here, so appears with lower intensity.

Distractor analysis

  • A is incorrect: the molecular ion is m/z 70, not 41; EI fragments are not “oxidation artifacts.”
  • B is chemically irrelevant because no halogens are present.
  • D is incorrect because different bond cleavages give fragments of different stabilities and therefore different abundances.

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Links associated with 2-methylbut-2-ene (2-methyl-2-butene)

The infrared spectrum of 2-methylbut-2-ene

The H-1 NMR spectrum of 2-methybut-2-ene

The C-13 NMR spectrum of 2-methylbut-2-ene

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